toq

从 toml 文件中快速获取所需内容

我创建了这个小型二进制程序，因为我发现当处理不依赖中间 json 文件步骤的 toml 文件时，几乎没有替代方案，所以我创建了一个。

安装

从 crates.io 下载二进制文件

cargo install toq

用法

二进制程序的设计是模仿 jq 的。虽然并没有实现 jq 的所有功能，但二进制程序在从 toml 文件中快速获取信息时仍然提供了功能。

例如，这是我们提供的 toml 文件

# test.toml

[[sources]]
name = "Some Name"
date = "Some date"

[[sources.times]]
time_1 = "1010010"
time_2 = "1010101"

[[sources.times]]
time_3 = "1111111"
time_4 = "0000000"


[[sources]]
name = "Other Name"
date = "Other date"

[[sources.times]]
time_1 = "202020"
time_2 = "20202020"

[[sources.times]]
time_3 = "222222"
time_4 = "00000000"

[[sources]]
name = "Other Other Name"
date = "Other Other date"

[[sources.times]]
time_1 = "30303030"
time_2 = "303030300"

[[sources.times]]
time_3 = "33333333"
time_4 = "000000000"

运行一个简单的查询，我们得到

$ toq '.' "test.toml"
{ sources = [{ date = "Some date", name = "Some Name", times = [{ time_1 = "1010010", time_2 = "1010101" }, { time_3 = "1111111", time_4 = "0000000" }] }, { date = "Other date", name = "Other Name", times = [{ time_1 = "202020", time_2 = "20202020" }, { time_3 = "222222", time_4 = "00000000" }] }, { date = "Other Other date", name = "Other Other Name", times = [{ time_1 = "30303030", time_2 = "303030300" }, { time_3 = "33333333", time_4 = "000000000" }] }] }

进一步探索

$ toq '.sources' "test.toml"
[{ date = "Some date", name = "Some Name", times = [{ time_1 = "1010010", time_2 = "1010101" }, { time_3 = "1111111", time_4 = "0000000" }] }, { date = "Other date", name = "Other Name", times = [{ time_1 = "202020", time_2 = "20202020" }, { time_3 = "222222", time_4 = "00000000" }] }, { date = "Other Other date", name = "Other Other Name", times = [{ time_1 = "30303030", time_2 = "303030300" }, { time_3 = "33333333", time_4 = "000000000" }] }]

遍历数组

$ toq '.sources[]' "test.toml"
{ date = "Some date", name = "Some Name", times = [{ time_1 = "1010010", time_2 = "1010101" }, { time_3 = "1111111", time_4 = "0000000" }] }
{ date = "Other date", name = "Other Name", times = [{ time_1 = "202020", time_2 = "20202020" }, { time_3 = "222222", time_4 = "00000000" }] }
{ date = "Other Other date", name = "Other Other Name", times = [{ time_1 = "30303030", time_2 = "303030300" }, { time_3 = "33333333", time_4 = "000000000" }] }

遍历嵌套数组

$ toq '.sources[].times[]' "test.toml"
{ time_1 = "1010010", time_2 = "1010101" }
{ time_3 = "1111111", time_4 = "0000000" }
{ time_1 = "202020", time_2 = "20202020" }
{ time_3 = "222222", time_4 = "00000000" }
{ time_1 = "30303030", time_2 = "303030300" }
{ time_3 = "33333333", time_4 = "000000000" }

在嵌套数组中选择一个条目将过滤出仅具有这些条目的对象

$ toq '.sources[].times[].time_1' "test.toml"
"1010010"
"202020"
"30303030"

如您所见，结合此二进制程序和其他 CLI 工具具有潜在的可能性，以在需要时加速此文件类型的文本处理。