rust-resp-protocol

REDis序列化协议

安装

将 resp-protocol 添加到 Cargo.toml

[dependencies]
resp-protocol = "0.0.10"

用法

use resp_protocol;

类型

• 简单字符串
• 错误
• 整数
• 批量字符串
• 数组

简单字符串

示例

值

"+OK\r\n"

构建

use resp_protocol::SimpleString;

let simple_string: SimpleString = SimpleString::new(b"OK");

解析

use resp_protocol::SimpleString;

let string: &str = "+OK\r\n";
let simple_string: SimpleString = SimpleString::parse(string.as_bytes(), &mut 0, &string.len()).unwrap();

错误

示例

值

"-ERROR\r\n"

构建

use resp_protocol::Error;

let error: Error = Error::new(b"ERROR");

解析

use resp_protocol::Error;

let string: &str = "-ERROR\r\n";
let error: Error = Error::parse(string.as_bytes(), &mut 0, &string.len()).unwrap();

整数

示例

值

":100\r\n"

构建

use resp_protocol::Integer;

let integer: Integer = Integer::new(-100i64);

解析

use resp_protocol::Integer;

let string: &str = ":-100\r\n";
let integer: Integer = Integer::parse(string.as_bytes(), &mut 0, &string.len()).unwrap();

批量字符串

示例

值

"$6\r\nfoobar\r\n"

构建

use resp_protocol::BulkString;

let bulk_string: BulkString = BulkString::new(b"foobar");

解析

use resp_protocol::BulkString;

let string: &str = "$6\r\nfoobar\r\n";
let bulk_string: BulkString = BulkString::parse(string.as_bytes(), &mut 0, &string.len()).unwrap();

数组

示例

值

"*0\r\n"                            // empty array
"*2\r\n$3\r\nfoo\r\n$3\r\nbar\r\n"  // bulk strings array
"*2\r\n:1\r\n$6\r\nfoobar\r\n"      // mixed types array

构建

use resp_procotol::{Array, ArrayBuilder, RespType, Integer, BulkString};

let mut array_builder: ArrayBuilder = ArrayBuilder::new();
array_builder.insert(RespType::Integer(Integer::new(100)));
array_builder.insert(RespType::BulkString(BulkString::new(b"foobar")));

let array: Array = array_builder.build();
println!("{:?}", array); // Array(b"*2\r\n:100\r\n$6\r\nfoobar\r\n")

解析

use resp_protocol::Array;

let string = "*2\r\n$3\r\nfoo\r\n$3\r\nbar\r\n";
let array = Array::parse(string.as_bytes(), &mut 0, &string.len()).unwrap();
println!("{:?}", array); // Array(b"*2\r\n$3\r\nfoo\r\n$3\r\nbar\r\n")