hsk

关于

返回简化汉字的HSK等级

用法

extern crate hsk;

use hsk::Hsk;

fn main() {
	let hsk_list = Hsk::new();
	let character: &str = "成为";
	let result: u8 = hsk_list.get_hsk(character);
	println!("{:?}", result); // --> 4
}

贡献者

• Preston Wang-Stosur-Bassett

许可证

MIT

lib.rs:

关于

返回简化汉字的HSK等级

用法

extern crate hsk;

use hsk::Hsk;

fn main() {
	let hsk_list = Hsk::new();
	let character: &str = "成为";
	let result: u8 = hsk_list.get_hsk(character);
	println!("{:?}", result); // --> 4
}