依赖排序

按依赖和组进行排序。

例如，解析类型实例化顺序或包引入顺序。

用法

考虑以下任务依赖关系

flowchart TB
    t0["Task 0"]
    t1["Task 1"]
    t2["Task 2"]
    t3["Task 3"]
    t4["Task 4"]
    t5["Task 5"]
    t6["Task 6"]
    t7["Task 7"]
    subgraph "Group A"
        t5 --> t2
    end
    subgraph "Group B"
        t6 --> t3
        t2 --> t4
        t3 --> t4
        t6 --> t4
    end
    t6 --> t1

您可以使用以下代码来解析序列

# use dependent_sort::DependentSort;
#[test]
fn execution_order() {
    let mut tasks = DependentSort::default();
    tasks += Task::new(&0);
    tasks += Task::new_with_dependent(&1, vec![&6]);
    tasks += Task::new_with_dependent(&2, vec![&5]).with_group(&"A");
    tasks += Task::new_with_dependent(&3, vec![&6]).with_group(&"B");
    tasks += Task::new_with_dependent(&4, vec![&2, &3, &6]).with_group(&"B");
    tasks += Task::new_with_dependent(&5, vec![]).with_group(&"A");
    tasks += Task::new_with_dependent(&6, vec![]).with_group(&"B");
    tasks += Task::new(&7);
    let sorted = tasks.sort().unwrap();
    for task in &sorted {
        println!("{:?}", task);
    }
    let ids = sorted.into_iter().map(|task| *task.id).collect::<Vec<_>>();
    assert_eq!(ids, vec![5, 2, 0, 7, 6, 3, 4, 1])
}

输出以下构建顺序，并一起执行相同组内的任务

Task { id: 5, group: Some("A"), dependent_tasks: [] }
Task { id: 2, group: Some("A"), dependent_tasks: [5] }
Task { id: 0, group: None, dependent_tasks: [] }
Task { id: 7, group: None, dependent_tasks: [] }
Task { id: 6, group: Some("B"), dependent_tasks: [] }
Task { id: 3, group: Some("B"), dependent_tasks: [6] }
Task { id: 4, group: Some("B"), dependent_tasks: [2, 3, 6] }
Task { id: 1, group: None, dependent_tasks: [6] }